3分之2 Y= y- 4
~thx~
方程式一問 6(詳列步驟)
2009-04-01 12:39 am
回答 (3)
2009-04-01 3:57 am
✔ 最佳答案
相信你指 Y = y2/3 y = y - 4
2/3 y - y = y - 4 - y
-1/3 y = y - y - 4
-1/3 y = 0 - 4
-1/3 y = - 4
(-1/3 y)/(-4) = - 4/(-4)
1/12 y = 1
12*1/12 y = 12*1
1*y = 12
y = 12
2009-04-01 12:47 am
2y/3 = y - 4
_2y = 3y - 12 (左右同時乘以 3)
_- y = - 12 (左右同時減以 3y)
__y = 12 (左右同時乘以 - 1)
_2y = 3y - 12 (左右同時乘以 3)
_- y = - 12 (左右同時減以 3y)
__y = 12 (左右同時乘以 - 1)
2009-04-01 12:45 am
3分之2 Y= y- 4
y=(y- 4)*2分之3
y=3y/2-6
6+y=3y/2
(6+y)2=3y
12+2y=3y
12=3y-2y
12=y
y=12
y=(y- 4)*2分之3
y=3y/2-6
6+y=3y/2
(6+y)2=3y
12+2y=3y
12=3y-2y
12=y
y=12
參考: me
收錄日期: 2021-04-13 16:33:07
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