✔ 最佳答案
log2 = z/4
log3= y - log5 = y- [ 1-log2]=y+(z/4)-1
log4 = z/2
log5 = 1-log2 = 1- (z/4)
log6 = log3 + log2, now you do the rest for this,
log7 = log14 - log2
log8 = 3log2, now you do the rest for this, too!
log9 = 2 log3, now you do the rest for this.
See! you must have forgotten laws of logarithm! Otherwise what is there in this?