三角形面積

2009-03-29 8:28 am
呢題要用希羅公式*

在△ABC中,設 s = 1/2 (a + b + c)而 s- a = 5.7cm, s - b = 9.3cm 及 s - c = 7.4cm。求△ABC的周界。


唔該哂!!!! :D

回答 (1)

2009-03-29 8:45 am
✔ 最佳答案
s = (a + b + c)/2 ....(i)

s-a = 5.7
s-b = 9.3
s-c = 7.4

(s-a)+(s-b)+(s-c) = 5.7+9.3+7.4
3s-(a+b+c) = 22.4 .....(ii)

Sub (i) into (ii),
3(a+b+c)/2 -(a+b+c) = 22.4
(3/2-1)(a+b+c) = 22.4
a+b+c = 44.8

所以,△ABC的周界為44.8 cm
參考: myself


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