That's sounds simple enough, wavelength of red light is larger than that of white light, so it is faster!
That comes to a question, do we need to ignore their frequency?
As a metaphor, I can tell all of you a story:
A diver jumps into the bottom of swimming pool and starts running. This guy runs with the same frequency all the time [frequency kept constant for a wave], but cannot maintain its normal stride due to higher resistance. Will this guy run faster than that of the other diver which could run with much higher frequency in his steps? May not!!!!
So, red light is faster than violet light provided only frequency is not taken into account, since violet has higher frequency than red light in the electromagnetic spectrum
Is there anything missed when considering frequency? From our experience, frequency kept constant in all medium, for example, a water wave has its frequency kept constant when entering a shallower region.
Could we treat water wave with EM wave in the same way? Yes, they are waves and in the same time transverse waves.
So the difference in frequency continues even when entering another medium, the only stance to say speed is equal to wavelength time frequency is that, frequency of red light and purple light is the same when they are entered from white light, and the color they appear to us is not due to their unique frequency, but their unique wavelengths?
Who agree with me? Or someone agree velocity is independent with frequency for this case
喂 00, 你比相對論網址比我做咩? 搏最佳答案?
One point missed: The larger a ray bends towards normal, the smaller the angle of refraction. The smaller the angle of refraction, the smaller is sin(r). And n=(v1/v2)=(sini/sin)
I mean (sin[i]/sin[r])
請各位到此網頁的人注意: Velocity of different waves are different in the same medium, this is proved by the experiment of dispersion using prism.
Since n-=(v1/v2), where n is the refractive index 你地唔信可以問物理老師 所以唔駛理002 呢一句說話: Again, the key is "speed of light of all wavelength is the same while traveling in the same medium".
velocity of speed of any EM wave is the same only in vacuum