What is the answer to (30x3 + 4x2 - 150)(3x - 5)?

(30x^3 + 4x^2 - 150)(3x - 5)
= 30x^3*3x + 4x^2*3x - 150*3x - 30x^3*5 - 4x^2*5 + 150*5
= 90x^4 + 12x^3 - 450x - 150x^3 - 20x^2 + 750
= 90x^4 + 12x^3 - 150x^3 - 20x^2 - 450x + 750
= 90x^4 - 138x^3 - 20x^2 - 450x + 750

First show the above equation in terms of y through manpulating the equation. a million) circulate all the words that don't contain y to the superb hand side (RHS). try this through subtracting those words from the two facets of the equation. you're able to try this because of fact if 2 issues are equivalent, and you subtract a similar element from the two a type of issues, the outcomes are nevertheless equivalent. a similar applies to any arithmetic operation. then you definately get: 3y = 5 - 4x2 - 8x 2) Divide the two facets through three and rearrange the RHS words so as of powers of x: y = -4/3 x2 -8/3 x + 5/3 3) i'm undecided what the question is as to solutions. You did no longer say on your question. one element you're able to do is plot the function through substituting various values for x and recording the corresponding values for y. yet another that is completed is to discover the roots of the equation, that are the values of x such that y = 0. For a quadratic equation there might nicely be 0, a million, or 2 genuine roots. There are continuously 2 complicated roots although if the two could be equivalent. You try this utilising the quadratic formulation for 0 = a x2 + bx + c: x = (-b +/- sqrt(b2 - 4ac) ) / 2a

90x^4 + 12x³ _____- 450x
_____- 150x³ - 20x² ____+ 750

90x^4 - 138x³ -20x² - 450x + 750

(30x3 + 4x2 - 150)(3x - 5)

= 30x3(3x - 5) + 4x2(3x - 5) - 150(3x - 5)
=90x4 - 150x3 + 12x3 -20x2 - 450x + 750
=90x4-138x3 - 20x2 - 450x +750

(30x^3 + 4x^2 - 150)(3x - 5)
= 90x^4 - 150x^3 + 12x^3 - 20x^2 - 450x + 750
= 90x^4 - 138x^3 - 20x^2 - 450x + 750

Done

(-52 x -15) = 780

Distribute the binomial through the trinomial

30x³(3x-5) + 4x²(3x-5) - 150(3x-5)

90x⁴ - 150x³ + 12x³ - 20x² - 450x + 750

90x⁴ - 138x³ - 20x² - 450x + 750

780

Just distribute each term in the first parentheses to each term in the second parentheses.
90x^4-150x^3+12x^3-20x^2-450x+750 Combine like terms
90x^4-138x^3-450x+750

why dont you ask how to do this type of problem rather than just ask for the answer. Getting easy feeds for homework is fun and all,

but I am sure a test will come up somewhere and I am a little confident that you will not be allowed to use yahoo answers on your test.