Please solve: 2 + x (less than or equal to) 6?

2 + x ≤ 6

x ≤ 4

2 + x <= 6
x <= 6 - 2
x <= 4

Answer: x <= 4

x^2 + 7x + 6 <= 6 x^2 + 7x <= 0 || Subtract 6 from the two facets x(x+7) <= 0 So there you bypass. build your signs and warning signs table, and calculate that. x^2 + 7x + 6 could properly be factored (x + 6)(x + a million), yet you do no longer choose for the zeroes of that - you elect for to get the <= 6 section. consequently, you may subtract 6 from the two facets. that's the step you're lacking.

2 + x ≤ 6
x ≤ 6 - 2
x ≤ 4

2 + x < 6
x < 6 - 2
Ans : x < 4
remember that the inequality sign < should have a line beneath it because there is a possibility that it may be equal to 6.

x is less than or equal to 4
pretend (<) means less than or equal to
2 + x (<) 6
= -2 -2

= x (<) 4


sorry if i'm wrong