how do i solve-10x=-20?

2009-03-26 3:21 pm

回答 (10)

2009-03-26 3:28 pm
✔ 最佳答案
okay i dont know how good ur knowledge is so i give full explanation

-10x = -20

0 = -20+10x (put -10x on right hand side to make it positive)

20 = 10x (put the 20 on the left hand side to make it positive)

now how many times do we have to multiply 10 to get 20?

so 20/10 = x

so x = 2
2009-03-26 3:31 pm
-10x=-20
-10x/-10=-20/-10
x=2
2009-03-26 3:25 pm
-10x = -20
Divide both sides by -10 to get a single x.
-10x / -10 = -20 / -10
x = 2
2009-03-26 3:43 pm
divide both sides by -10 like this

-10x=-20
divide by -10 on both sides to get
x=2
2009-03-26 3:28 pm
well first you have your problem: -10x = -20
bring -10 to the other side by diving both sides by -10
(-10/)-10x(-10/)-20 which cancels out the -10 on the right and brings it to the left:
x = -20/-10
x = 2
參考: hope it helps
2009-03-26 3:27 pm
-10x = -20
x = -20/-10
x = 2
2009-03-26 3:26 pm
10 x = 20
x = 2
2009-03-26 3:26 pm
-10x = -20
x = -20/-10
x = 2
參考: my pet dog
2009-03-26 3:25 pm
-10x = -20
=> x = -10 / -20
=> x = 1/2
2009-03-26 3:25 pm
x = -20 / -10
x = 2


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