A stone of mass 0.20 kg is attached to an extremely light thread, whose mass can be considered negligible, and swung around a fixed vertical axis Y so that the stone undergoes circular motion in a horizontal plane. The length of thread from the stone to the axis of rotation Y is L = 2.6 m and the thread makes an angle of θ = 73.0 ° to the vertical.
What is the tension in the thread?
What is the magnitude of the centripetal force on the stone?
Help calculating tension and magnitude of the centripetal force!!!?
2009-03-26 9:20 am
回答 (3)
2009-03-26 10:00 am
✔ 最佳答案
draw a diagram of a stone with a downward force for gravity, a horizontal force (to the right) for the centripetal force, and a diagonal force (up to the left) for the tension force of the stringyou know the magnitude of the downward force (W = mg)
then you can calculate the tension in the string because you know the vertical component of the tension must be equivalent to the stone's weight and you know the direction of that vector
then you can calculate the magnitude of the centripetal force by finding the horizontal component of the tension
that's probably not what your teacher wants you to do, but I'd probably argue that it's a valid solution
2009-03-26 9:55 am
tension is equal to weight
centripetal force=mv^2/r
calculate yourself
centripetal force=mv^2/r
calculate yourself
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