how to factorise a quadratic?
回答 (8)
2009-03-25 11:34 am
✔ 最佳答案
x^2-169=(x+13)(x-13) answer//x^2 - 16=(x+4)(x-4) answer//
2009-03-25 6:28 pm
x^2 - 169 = x^2 - 13^2
= (x+13)(x-13)
Similarly
x^2 - 16 = x^2 - 4^2
= (x+4)(x-4)
Factorizing means finding out the proper factors of what you are given with.
= (x+13)(x-13)
Similarly
x^2 - 16 = x^2 - 4^2
= (x+4)(x-4)
Factorizing means finding out the proper factors of what you are given with.
2009-03-25 6:27 pm
x² – 169 = (x + 13)(x – 13)
x² – 16 = (x + 4)(x – 4)
x² – 16 = (x + 4)(x – 4)
2009-03-25 6:53 pm
a^2 - b^2 = (a + b)(a - b)
1)
x^2 - 169
= x^2 - 13^2
= (x + 13)(x - 13)
2)
x^2 - 16
= x^2 - 4^2
= (x + 4)(x - 4)
1)
x^2 - 169
= x^2 - 13^2
= (x + 13)(x - 13)
2)
x^2 - 16
= x^2 - 4^2
= (x + 4)(x - 4)
2009-03-25 6:35 pm
x^2 - 169 = x^2 - 13^2 = (x+13) (x-13)
x^2 - 16 = x^2 - 4^2 = (x+4) (x-4)
x^2 - 16 = x^2 - 4^2 = (x+4) (x-4)
2009-03-25 6:33 pm
just get the square rout and use opposite sign for its factors
therefore:
169=13x13
and x^2= x(x)
to factor
x^2-169= (x+13) (x-13)
check:
x+13
x-13
________________
x^2-13x
+13x -169
__________________
x^2 0 -169
therefore:
x^2-169
2nd question x
16=4x4
x^2=x(x)
therefore
x^2-16 = (x-4) (x+4)
ok
once you get the Square root, just add it to x for the first factor, and subtract it to x for the second factor
ok, good luck
remember square root is the number you multiply by itself to get the number.
therefore:
169=13x13
and x^2= x(x)
to factor
x^2-169= (x+13) (x-13)
check:
x+13
x-13
________________
x^2-13x
+13x -169
__________________
x^2 0 -169
therefore:
x^2-169
2nd question x
16=4x4
x^2=x(x)
therefore
x^2-16 = (x-4) (x+4)
ok
once you get the Square root, just add it to x for the first factor, and subtract it to x for the second factor
ok, good luck
remember square root is the number you multiply by itself to get the number.
參考: engineer
2009-03-25 6:32 pm
(x-y)(x+y)
Just square root the second term, and substitute that answer to "y".
Therefore answer is (x-13)(x+13). Always remember that rule when you see x2-(a number that can be square-rooted)
Just square root the second term, and substitute that answer to "y".
Therefore answer is (x-13)(x+13). Always remember that rule when you see x2-(a number that can be square-rooted)
參考: My high knowledge of mathematics LOL
2009-03-25 6:26 pm
Factor Quadratic Equations of the Form ex² +cx +d, e=1
Step1Use the equation x²-10x+24 as an example and factorise it as the product of two binomials.
Step2Rewrite this equation as follows: x²-10x+24= (x ?)(x ?).
Step3Fill in the missing terms of the binomials with the two integers a and b whose product is +24, the constant term of x²-10x+24, and whose sum is -10, the coefficient of the x term. Since (-6) X (-4) = +24 and (-6) + (-4) = -10, then the correct factors of +24 are -6 and -4. So the equation x²-10x+24 = (x-4) (x-6).
http://www.ehow.com/how_2265712_factorise-quadratic-expression.html?ref=fuel&utm_source=yahoo&utm_medium=ssp&utm_campaign=yssp_art
Step1Use the equation x²-10x+24 as an example and factorise it as the product of two binomials.
Step2Rewrite this equation as follows: x²-10x+24= (x ?)(x ?).
Step3Fill in the missing terms of the binomials with the two integers a and b whose product is +24, the constant term of x²-10x+24, and whose sum is -10, the coefficient of the x term. Since (-6) X (-4) = +24 and (-6) + (-4) = -10, then the correct factors of +24 are -6 and -4. So the equation x²-10x+24 = (x-4) (x-6).
http://www.ehow.com/how_2265712_factorise-quadratic-expression.html?ref=fuel&utm_source=yahoo&utm_medium=ssp&utm_campaign=yssp_art
參考: GOD BLESS
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