Please solve: a + 8 - 2(a - 12) > 0?

2009-03-25 8:34 am

回答 (8)

2009-03-25 10:28 am
✔ 最佳答案
a + 8 - 2(a - 12) > 0
a + 8 - 2*a + 2*12 > 0
a + 8 - 2a + 24 > 0
a - 2a > -8 - 24
-a > -32
a < -32/-1
a < 32
2009-03-25 4:01 pm
a < 32
2009-03-25 3:41 pm
solve the brackets first
a + 8 - 2a + 24 >0
add the like terms
-1a + 32 > 0
move the variable to the other side of the equation (remember that it changes whether it is positive or negative when you do this)
32>1a
this equations ends up as:
32>a
or 32 is greater than a. meaning 'a' can be any number greater than 32
2009-03-25 3:52 pm
a + 8 -2(a -12) > 0
a + 8 -2a + 24 > 0
-a + 32 > 0
a < -32
2009-03-25 3:42 pm
a + 8 - 2(a - 12) > 0
a + 8 - 2a + 24) > 0
- a + 32 > 0
32 > a
a < 32
2009-03-25 3:40 pm
a + 8 - 2a + 24 > 0
32 > a
a < 32
2009-03-25 3:37 pm
a+ 8 -2a+24 > 0

-a +32 > 0
- 32 -32

-a > -32
/-1 /-1

a < 32
2009-03-25 3:41 pm
-a + 32 > 0

-a > -32

multiplying -1 on both sides, reversing the signs

a < 32


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