what is the pattern for the following sequence:
6, 12, 24, 48
please explain in details how you get the answer!! thank you
sequence problem
2009-03-25 7:09 am
回答 (2)
2009-03-25 7:29 am
✔ 最佳答案
T(1)=6T(2)=6x2 =2T(1)
T(3)=24=12x2=2T(2)=(2^2)T(1)
T(4)=48=2x24=2T(3)=(2^2)T(2)=(2^3)T(1)
so the pattern is T(n) = 2^(n-1) *6 =2^n x3
2009-03-25 3:47 pm
This is a G. S., that is a, ar, ar^2 , ar^3,...... ar^(n-1).
T(2)/T(1) = ar/a = r = 12/6 = 2.
rT(1) = T(2)
2a = 12
a = 6.
so T(n) = [6(2^(n-1)] = 3(2^n).
T(2)/T(1) = ar/a = r = 12/6 = 2.
rT(1) = T(2)
2a = 12
a = 6.
so T(n) = [6(2^(n-1)] = 3(2^n).
收錄日期: 2021-04-25 22:38:36
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