maths 2006 ce paper 2

Q16

PAQ=180-42-28=110
AQP=APQ=(1/2)(180-110)=35
x=35-28=1 (A)

Q28
x-y=k
=> y=x-k
so the y-axis intercept = -k >0
So A and D are wrong
And the slope =1 >0
Since the selection of B is not match the operating , so the answer is C.

Q43
b=(ac)^(1/2)
=>b^2=ac
=>b/a = c/a

I.
log b ^2-log a^2 = log (a^2/b^2) =log [(a/b)^2]
log c^2-log b^2 =log (c^2/b^2)=log [(b/a)^2]
so log a^2 log b^2 and log c^2 are in AP.

II.
b^3/a^3=(b/a)^3
c^3/b^3=(c/b)^3=(b/a)^3
so a^3 ,b^3 and c^3 are in AP.

II.
sub a=1 , c =4 we have b=2

4^1-4^2 = -12 <> 4^2 - 4^4
so 4^a ,a^b,a^c are not in AP.

so the Ans of Q43 is A.

Q48
AB=(6-r)2=12-2r
so 12-2r=(6^2+6^2)^(1/2) =6(2)^(1/2)
so r= 6-3(2)^(1/2)//

D