C/C++ 數值(int) 拆成 二個數值(int)

#include<iostream.h>
#pragma argsused
int main(int argc, char* argv[])
{
int num,a,b;
cout<<"Enter a num of 10~99:";
cin>>num;
a=num/10;
b=num%10;
cout<<a<<endl;
cout<<b<<endl;
system("pause");
return 0;
}

10位數用除10找
個位數用%10找

我有另類想法QQ
應該可以輸入時用字元分別讀取
在要分別存入變數時強制變成整數存入

#include <stdio.h>

void main()
{
int n=24;
int x,y;

x = 24 %10;
y = 24 - x * 10;
}

/*
you can also use itoa() to convert integer to string and use atoi() to convert that back to integer after parsing it into smaller strings.
*/