Find the derivative of
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amaths dy/dx
2009-03-22 10:11 am
回答 (2)
2009-03-22 7:19 pm
2009-03-22 3:54 pm
y = [x - (x^2 - 1)^0.5]^0.5
d/dx = {0.5 [x- (x^2 - 1)^0.5]^(-0.5)} [ 1- 0.5 (2x) (x^2 - 1)^(-0.5)]
= [1 - x/(x^2 - 1)^0.5 ] / {2 [x - (x^2 - 1)^0.5]^0.5}
d/dx = {0.5 [x- (x^2 - 1)^0.5]^(-0.5)} [ 1- 0.5 (2x) (x^2 - 1)^(-0.5)]
= [1 - x/(x^2 - 1)^0.5 ] / {2 [x - (x^2 - 1)^0.5]^0.5}
收錄日期: 2021-04-23 20:37:20
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20090322000051KK00194