log7 1/49 = x
a. 2
b. -2
c: 1/2
d: -1/2
logx 1/64 = -3
a. 4
b. -4
c:1/4
d:-1/4
log4 x = -2
a: 1/16
b:1/8
c. -8
d. 16
Algebra Help!!!!!!!!!!!!!!!?
2009-03-21 5:49 am
回答 (5)
2009-03-21 5:58 am
✔ 最佳答案
Converting into exponential form7^x = 1/49
7^x = 49^-1
7^x = 7^-2
Comparing
x = - 2
x^ -3 = 1/64
x^ -3 = 64^-1
x^ -3 = 4^ -3
Comparing
x = 4
4^ -2 = x
1/(4)^2 = x
1/16 = x
x = 1/16
2009-03-21 7:18 pm
Question 1
1/49 = 7^x
x = - 2
OPTION b
Question 2
x^(-3) = 1/64
x = 4
OPTION a
Question 3
x = 4^(-2)
x = 1/16
OPTION a
1/49 = 7^x
x = - 2
OPTION b
Question 2
x^(-3) = 1/64
x = 4
OPTION a
Question 3
x = 4^(-2)
x = 1/16
OPTION a
2009-03-21 2:50 pm
1)
log_7(1/49) = x
7^x = 1/49
7^x = 1/(7^2)
7^x = 7^-2
x = -2
(answer b)
2)
log_x(1/64) = -3
x^-3 = 1/64
x^-3 = 1/(4^3)
x^-3 = 4^-3
x = 4
(answer a)
3)
log_4(x) = -2
4^-2 = x
x = 1/(4^2)
x = 1/16
(answer a)
log_7(1/49) = x
7^x = 1/49
7^x = 1/(7^2)
7^x = 7^-2
x = -2
(answer b)
2)
log_x(1/64) = -3
x^-3 = 1/64
x^-3 = 1/(4^3)
x^-3 = 4^-3
x = 4
(answer a)
3)
log_4(x) = -2
4^-2 = x
x = 1/(4^2)
x = 1/16
(answer a)
2009-03-21 1:09 pm
1. log7 7^(-2) = x, so x = -1/2
2. logx 8^(-2) = logx 4^(-3) = -3, so 4^(-3) = x^(-3), so x = 4
3. log4 x = -2, so 4^(-2) = x = 1/16
2. logx 8^(-2) = logx 4^(-3) = -3, so 4^(-3) = x^(-3), so x = 4
3. log4 x = -2, so 4^(-2) = x = 1/16
參考: None, simple logarithmic problems
2009-03-21 1:02 pm
b. -2
a. 4
a. 1/16
a. 4
a. 1/16
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