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回答 (2)
2009-03-21 5:36 pm
設f(x)=3x3-2x-9。
餘式=f(1/2)
=3(1/2)3-2(1/2)-9
=3/8-1-9
=- 77/8
餘式=f(1/2)
=3(1/2)3-2(1/2)-9
=3/8-1-9
=- 77/8
2009-03-21 6:25 am
3x^3-2x-9除不盡(2x-1)的.
By remainder theorem, 3x^3-2x-9=(2x-1)Q(x)+R
put x=1/2,
if 3x^3-2x-9除得盡(2x-1), R應該等於0
but
3(1/2)^3-2(1/2)-9=[2(1/2)-1]Q(X) +R
8/3-10=0+R
R=-77/3
R does not equal to 0,
so 3x^3-2x-9除不盡(2x-1)的
By remainder theorem, 3x^3-2x-9=(2x-1)Q(x)+R
put x=1/2,
if 3x^3-2x-9除得盡(2x-1), R應該等於0
but
3(1/2)^3-2(1/2)-9=[2(1/2)-1]Q(X) +R
8/3-10=0+R
R=-77/3
R does not equal to 0,
so 3x^3-2x-9除不盡(2x-1)的
參考: ME
收錄日期: 2021-04-23 20:35:52
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https://hk.answers.yahoo.com/question/index?qid=20090320000051KK01489