trigonometry ~slove equ

🎓 學業台教學

2009-03-20 4:59 am

2 cos^2 (x)+3sin(x)=3; 0=/< x <2pi, find x (3 answers)

回答 (1)

2009-03-20 6:23 am

✔ 最佳答案

2cos2x+3sinx=3
2(1-sin2x)+3sinx=3
2sin2x-3sinx+1=0
(2sinx-1)(sinx-1)=0
sinx=1/2 or sinx=1
x=π/6 or π/2 or 5π/6

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