5x + 7> 1/2(10x + 14)?

This is false. Here's why.

5x + 7 > (1/2)(10x + 14)

Multiply the half through the parenthesis:

5x + 7 > 5x + 7

Now subtract 7 from both sides:

5x > 5x

Now divide both sides by 5

x > x

A number is only equal to itself. It cannot be greater than or equal to itself, so this is FALSE

You could have subtracted 5x from both sides too, to get:

0 > 0

which is FALSE for the same reason, except you have two specific values that you're comparing.

So there is no real solution to this problem.

Suppose it were true:
2(5x+7 ) > 10x+14
10x+14 > 10x+14
answer :false:
anything cannot be greater than itself.
So, 5x + 7> 1/2(10x + 14) is false.

Is 1/2(10x + 14) = (1/2)(10x+14) or 1/[2(10x + 14)]?
In case of first its a contradiction.
In the second case I must kow which class if this for!

5x + 7> 1/2(10x + 14)?

i believe this question is wrong.

5x + 7> 1/2(10x + 14) (multiplying the whole thing by 2 to get rid of 1/2)
10x+14>10x+14

5x + 7 > 5x + 7
5x - 5x + 7 - 7 > 5x - 5x + 7 - 7
0 > 0
Your equation is equal.

5x + 7 > 1/2(10x + 14)
5x + 7 > (10x + 14)/2
5x + 7 > 5x + 7
0 > 0
(no solutions)

Distribute the 1/2 on the right-hand side into the parenthetical expression:
½(10x + 14) = (½ * 10x) + (½ * 14) = 5x + 7

Now we have:
5x + 7 > 5x + 7

It's easy to see that these are the same expression. So, no value of x will ever make this true. There is no solution.

5x + 7 (more than) 5x + 7

5x - 5x is more than 0

o is more than 0?

Can't do it - it doesn't work it is equal to not more than!

Distribute the 1/2 on the right:
5x+7>5x+7

Subtract 5x from both sides:
7>7

Since this statement is FALSE, there is no solution.

Will assume that you mean :-
5x + 7 > (1/2) (10x + 14)
10x + 14 > 10x + 14
Something fishy do you think ? !!