Help me solve this math problem?

4 + 3(2+3x) + 3x = 12x + 10
4+ 6 + 12x + 3x = 12x + 10

10 + 15x = 12x + 10

15x = 12x

3x =0

so x=0

4 + 6 + 9x + 3x = 12x + 10
10 + 12x = 12x + 10
Solution is all real numbers.

4 + 6 + 9x + 3x = 12x + 10

10 + 12x = 12x + 10

These equations are equal so x can have any value whatsoever.....i.e. any real number

4 + 6 + 9x +3x = 12x + 10
10 +12x = 12x +10
0 = 0
x = 0

16

=4 + 6 + 9x + 3x = 12x + 10
=9x + 3x - 12x = -4 -6 + 10
=0x = 0

Infinite solution.

4 + 6 + 9x + 3x = 12x + 10
10 - 10 = 12x - 9x - 3x

Therfore:
x = 0

3(2+3x)=12x-3x+10-4
6+9x=9x+6
any value of x is valid.

4 + 3(2 + 3x) + 3x = 12x + 10
4 + 3*2 + 3*3x + 3x = 12x + 10
4 + 6 + 9x + 3x = 12x + 10
12x - 12x = -4 - 6 + 10
0 = 0
(infinite solutions)

4 + 6 + 9x +3x = 12x + 10

10 +12x = 12x +10

0 = 0

x = 0