In the figure, AB=AC. A straight line meets AB and AC at D and E respectively. It also meets BC When produced at F. Prove That AD < AE.
http://www.pic-upload.de/18.03.09/yn5ll.jpg
or
http://www.pic-upload.de/view-1694505/-12.jpg.html
數學問題 20點 【急】
2009-03-19 1:17 am
回答 (4)
2009-03-19 2:55 am
✔ 最佳答案
http://www.pic-upload.de/view-1694962/Solution.jpg.htmlAD=AF
AE=AF+FE
AE=AD+FE
So, AD<AE
2009-03-18 18:56:07 補充：
AD=AG
AE=AG+GE
AE=AD+GE
-.-睇錯
2009-03-20 10:49 pm
NO thats all of the question
2009-03-20 3:55 am
In the figure, AB=AC. A straight line meets AB and AC at D and E respectively. It also meets BC When produced at F. Prove That AD < AE.
In the figure, AB=AC. A straight line meets AB and AC at D and E respectively. It also meets BC When produced at F. Prove That AD < AE.
In the figure, AB=AC. A straight line meets AB and AC at D and E respectively. It also meets BC When produced at F. Prove That AD < AE.
In the figure, AB=AC. A straight line meets AB and AC at D and E respectively. It also meets BC When produced at F. Prove That AD < AE.
In the figure, AB=AC. A straight line meets AB and AC at D and E respectively. It also meets BC When produced at F. Prove That AD < AE.
2009-03-19 2:14 am
Is there any information missing?
Such as AB is perpendicular to DF.
Such as AB is perpendicular to DF.
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