急!!derivative

2009-03-17 7:34 am
u(w) = (1- e ^(-ab)) / a

For this equation, do i use quotient rule? or how should i do?
derivative of -e^-ab is it become e^ab ?
更新1:

with a >0 and b >0

更新2:

derivative of u(w)

更新3:

by quotient rule, is the answer like this? u'(w) = [(e^ab)(ab)'a - (1-e^-ab)a'] / a^2

更新4:

if the answer is correct, what is the u''(w)?

回答 (4)

2009-03-18 6:22 am
✔ 最佳答案
Yes ,I wanna ask what is the variable in this function?

2009-03-17 22:22:38 補充:
As follows:

圖片參考:http://hk.geocities.com/stevieg_1023/0DPP3.gif
2009-03-18 2:53 am
LHS is a function u with variable w,
RHS is just a constant w.r.t. w, thus u'(w)=0.
2009-03-17 8:02 am
if a, b are real constants with a being non-zero
then u(w) is a constant function
its derivative should be 0

do you actually mean u(a) with b as a constant?
2009-03-17 7:59 am
Should u(w) be u(a) or u(b) ?
Otherwise, derivative of -e^-ab become (e^ab)(ab)'


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