(3/x-2)-(6/x)=1. what is the sum of the solution?

(3/x-2)-(6/x)=1
3(x)-6(x-2)=x^2-2x
-3x+12=x^2-2x
x^2-2x+3x-12=0
x^2+x-12=0

Sum of roots = -b/a
=-1/1
=-1

==============OR==============
x^2+x-12=0
(x+4)(x-3)=0
x=-4 or 3
-4+3=-1

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3/(x - 2) - 6/x = 1
x[x - 2][3/(x - 2) - 6/x] = x[x - 2][1]
3x - 6(x - 2) = x(x - 2)
3x - 6x + 12 = x^2 - 2x
x^2 - 2x + 6x - 3x - 12 = 0
x^2 + x - 12 = 0
x^2 + 4x - 3x - 12 = 0
(x^2 + 4x) - (3x + 12) = 0
x(x + 4) - 3(x + 4) = 0
(x + 4)(x - 3) = 0

x + 4 = 0
x = -4

x - 3 = 0
x = 3

∴ x = -4 , 3

ambiguous. my interpretation

((3/x) – 2) – (6/x) = 1
(3/x) – 2 – (6/x) – 1 = 0
–(3/x) –3 = 0
3/x = –3
x = –1

that is the solution. I don't know what "sum of the solution" means?

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