I'm having trouble remembering my algebra.
If I have 1.06^x = 2.0544, how do I solve for X?
Thank you.
Solve for something to the X power?
2009-03-15 9:23 am
回答 (5)
2009-03-15 9:33 am
✔ 最佳答案
1.06^x = 2.0544xln(1.06)=ln(2.0544)
.....ln(2.0544)
x=------------------
.....ln(1.06)
x=12.356 answer//
2009-03-15 4:48 pm
xLn1.06=Ln2.0544
x=12.35622663
=================================================
CHECH:1.06^12.35622663=2.0544
x=12.35622663
=================================================
CHECH:1.06^12.35622663=2.0544
2009-03-15 4:47 pm
1.06^x = 2.0544
log(1.06^x) = log(2.0544)
(x)log(1.06) = log(2.0544)
x = log(2.0544)/log(1.06)
log(1.06^x) = log(2.0544)
(x)log(1.06) = log(2.0544)
x = log(2.0544)/log(1.06)
2009-03-15 4:28 pm
Use the natural logarithm:
ln(1.06^x) = xln(1.06)
.: xln(1.06) = ln(2.0544)
x = ln(2.0544)/ln(1.06)
x =~ 12.36
ln(1.06^x) = xln(1.06)
.: xln(1.06) = ln(2.0544)
x = ln(2.0544)/ln(1.06)
x =~ 12.36
2009-03-15 4:30 pm
Changing to a log function:
x = log(base 1.06)2.0544
Using log rules:
x = log 2.0544/log 1.06
x = 12.356
x = log(base 1.06)2.0544
Using log rules:
x = log 2.0544/log 1.06
x = 12.356
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