can someone solve this equation, 2x^2 + 12x+ 40= 360?

2x^2+12x+40-360=0
2x^2+12x-320=0
x^2+6x-160=0
(x+16)(x-10) =0
x+16=0 x-10=0
x=-16 x=10 x={-16,10} answer//

135=180(n-2)
.......-------------
...........n

135n=180n-360
135n-180n=-360
-45n=-360
n=8 answer//

ya sure.. the first answer is x = -16, 10
u can divide the whole thing by 2 and then factorise... if u cant get don hesitate to contact me..

135/180 = (n-2)/n
135/45 = (n-2)/2
3 = (n-2)/2
n-2 = 6
n = 8

Divide bothsides to 2,then x^2+6x-160=0
then (x-10)(x+16)=0,x=10 & x=-16
==================================================
135n=180n-360
360=45n
n=8

1)
2x^2 + 12x + 40 = 360
x^2 + 6x + 20 = 180
x^2 + 6x + 20 - 180 = 0
x^2 + 6x - 160 = 0
x^2 + 16x - 10x - 160 = 0
(x^2 + 16x) - (10x + 160) = 0
x(x + 16) - 10(x + 16) = 0
(x + 16)(x - 10) = 0

x + 16 = 0
x = -16

x - 10 = 0
x = 10

∴ x = -16 , 10

= = = = = = = =

2)
135 = 180(n - 2)/n
135n = 180(n - 2)
135n = 180*n - 180*2
135n = 180n - 360
135n - 180n = -360
-45n = -360
n = -360/-45
n = 8

x^3=13.3
this simplified is
4.43

2x² + 12x + 40 = 360
2x² + 12x + 40 - 360 = 0
2x² + 12x - 320 = 0
x² + 6x - 160 = 0
(x - 10)(x - 16) = 0
x - 10 = 0 OR x - 16 = 0
x = 10 OR x = 16

135 = 180(n - 2) / n
135n = 180(n - 2)
135n = 180n - 360
135n - 180n = -360
-45n = -360
45n = 360
n = 360 / 45
n = 8

x = 10 or -16

n = 8