solve these two basic algebra equations show steps EASY POINTS! :)?

1)
(3y - 2)/5 = (6y - 5)/11
3y - 2 = 5(6y - 5)/11
11(3y - 2) = 5*6y - 5*5
33y - 22 = 30y - 25
33y - 30y = 22 - 25
3y = -3
y = -3/3
y = -1

2)
(5k + 1)/6 = (3k - 2)/3
5k + 1 = 6(3k - 2)/3
5k + 1 = 2(3k - 2)/1
5k + 1 = 2(3k - 2)
5k + 1 = 2*3k - 2*2
5k + 1 = 6k - 4
5k - 6k = -1 - 4
-k = -5
k = -5/-1
k = 5

enable the prepare grew to become into shifting with velocity x km/h & distance travelled is 90km. consequently time taken = ninety/x hr. Now in accordance to ques prepare is going 3km/hr speedier so velocity of prepare = x+3 km. Distance is 90km. consequently time taken is ninety/(x+3) hr. Now in accordance to ques (ninety/x) - a million = ninety/(x+3) fixing this we get x= 15 or x = -18 because of the fact that x is velocity & velocity won't be able to be adverse x=-18 is surpassed over consequently velocity of prepare is 15km/hr consequently time taken = ninety/15=6hrs. If velocity is greater by utilizing 3km/h time taken would be 6-a million = 5hrs.

Question 1
33y - 22 = 30y - 25
3y = - 3
y = - 1

Question 2
15k + 3 = 18k - 12
15 = 3k
k = 5

1)

(3y - 2) / 5 = (6y - 5) / 11

cross multiplying

11* (3y - 2) = 5 * (6y - 5)

opening braces

33y - 22 = 30y - 25

33y - 30y = 22 - 25

3y = -3

y = -1


2)

(5k + 1 ) / 6 = (3k - 2) / 3

cross multiplying

3 * (5k + 1 ) = 6 * (3k - 2)

opening braces

15k + 3 = 18k - 12

3 + 12 = 18k - 15k

15 = 3k

3k = 15

k = 15 / 3

k = 5

question 1:
multiply both sides by 5 and 11
so it looks like:
11(3y-2)=5(6y-5)
distribute
33y-22=30y-25
add 22
33y=30y-3
subtract 30y
3y=-3
divide by 3
y=-1

3y - 2 = 6y -5

Is this the way you want it to be answered? I don't get what is the 5 and 11? Same in question 2.

Cross multiply
Basically, it means that you multiply the numerator of one by the denominator of the other, and then set them equal

(3y - 2) / 5 = (6y - 5) / 11

You will get
(3y - 2) * (11) = (6y - 5) * (5)

Distribute the terms on each side, and you will get
33y - 22 = 30y - 25

Subtract 30y from both sides
33y (-30y) - 22 = 30y (-30y) - 25

3y -22 = -25
Add -22 to both sides
3y - 22 (+22) = -25 (+22)

3y = -3
y = -1

Do the same with the next one
(5k + 1) * (3) = (3k - 2) * 6
15k + 3 = 18k - 12
-3k = -15
k = 5