find dy/dx
y=(x^x)(In x)
math derivative 7
2009-03-15 1:09 am
回答 (1)
2009-03-15 1:21 am
✔ 最佳答案
Let u = x^xln u = x ln x
1/u(du/dx) = ln x + 1
so du/dx = u(ln x + 1).
y = x^x ln x
= u ln x
dy/dx = u/x + ln x ( du/dx)
= (x^x)/x + ln x[u(ln x + 1)]
= x^(x -1) + ln x(ln x + 1)x^x.
收錄日期: 2021-04-25 22:36:47
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