How do I rearrange this logarithm? 4.19=-log x?

2009-03-13 4:29 pm

I just need to know how to solve for x; it should be easy but I'm getting the wrong answer

What do I do with the negative sign? Thank you!

更新1:

Hm... that's what I should, so I gues the experimental data I found must be wrong Thanks!

回答 (7)

[匿名]

2009-03-13 4:39 pm

✔ 最佳答案

You need to know the relationship between exponentials and logarithms:
b^n = x
is equivalent to:
n = log base b (x)
So although you didn't specify the base we generally assume log means log base 10. (In some applications log can mean log base e or ln.)

4.19=-log x
-4.19=log x
10 ^( -4.19) = x
so:
x = .000064565

OIf that does not check with you answer. I would consider that possible log x was ln x
and x = e^(-4.19)

x = .01515

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