to produce interference,a signal of frequency1.4kHz is fed into two loudspeakers.how far a part should the two loudspeakers be placed if they are to be separated by a distance equal to 2 wavelengths?V=340m/s
detail thx
physic question
2009-03-13 5:01 am
回答 (1)
2009-03-14 7:34 pm
✔ 最佳答案
The question has already said "..... they are to be separated by a distance of 2 wavelengths"wavelength = velocity of sound/frequency = 340/1400 m
Two wavelengths = 2x(340/1400) m
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