可吾可以幫我解答一條數學題目=]

2009-03-13 1:54 am
設a和b是常數, r是方程 ax+b=0的根.問 ar+b的值是多少?

回答 (4)

2009-03-13 1:58 am
✔ 最佳答案
因為r是 方程ax+b=0的根
所以代 r 去方程
ar+b=0
參考: ME
2009-03-13 2:43 am
ar+b的值是 0 .
2009-03-13 2:42 am
Since r is a root of the equation ax + b = 0,

by definition, x = r satisfies the equation.

So, ar + b = 0 where a is not equal to 0.
2009-03-13 2:22 am
0?


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