請用微積分計出兩者相撞既時間

2009-03-12 5:53 am
有兩個 point mass, 質量為 M 同 m, 相距 R 米, 兩者越接近時萬有引力越上升....

假設:
1. 兩者相對既初速係零
2. 不受第三者既萬有引力影響

請用微積分計出兩者相撞既時間.

回答 (4)

2009-03-18 1:01 pm
✔ 最佳答案
我相信這條問題很難計算,因為那兩個point mass都會互相移動。

2009-03-18 05:01:51 補充:

圖片參考:http://i212.photobucket.com/albums/cc82/doraemonpaul/yahoo_knowledge/crazygravitation/crazygravitation1.jpg


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圖片參考:http://i212.photobucket.com/albums/cc82/doraemonpaul/yahoo_knowledge/crazygravitation/crazygravitation9.jpg


參考資料:
My Physics and Maths knowledge

2009-03-19 05:54:33 補充:
其實這題嚴格上來說是要用狹義相對論和廣義相對論來計算(因為這個系統的force是有機會極大,導致這個系統的velocity有機會極大。)狹義相對論的maths我識,但是廣義相對論的maths我就唔識。而且我找過廣義相對論的maths(http://en.wikipedia.org/wiki/Mathematics_of_general_relativity),找不到任何平常我們熟悉的terms,所以如何利用廣義相對論的maths去表達這題我就實在無能為力了,因此我只能無奈地用牛頓力學去計算。
2009-03-17 7:45 pm
回002, 呢個係全整條問題首先要解決既野. 不過亦都係最易解決既.

2 point mass M and m,
Reduced mass m(red)=Mm/(M+m)

2009-03-18 17:37:58 補充:
to doraemonpaul, 後面有幾張睇唔到...
2009-03-12 4:45 pm
回答者001的答案是有問題的。
a 不能寫成(v - u) / t,這只適合於均加速度的運動,並不適用於這例。
2009-03-12 7:18 am
F=GMm/R^2
=>ma=GMm/R^2
=>(v-u)/t=GM/R^2
=>v/t=GM/R^2
=>t=vR^2/GM//



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