For triangle ABC ( order in anti-clockwise direction), D is a point on AB and E is a point on AC such that CD perpendicular to AB and BE perpendicular to AC. Prove that angle EDC = angle EBC by proving of similar triangles ( theorems of circle is not allowed).
Similar triangles
2009-03-12 5:18 am
回答 (1)
2009-03-12 5:34 am
✔ 最佳答案
Let DC and DE meet at point F,then△BFD ~△CFE,
so in BF/DF = CF/EF,and ㄥBFC = ㄥDFE
so△BFC~△DFE (SAS)
so angle EDC = angle EBC
收錄日期: 2021-04-21 22:04:52
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