✔ 最佳答案
1.
a)設角為θ
扇形周界就係:
r+r+rθ=20+4π
2r+rθ=20+4π
孤度問題多數r都係整數,而度數多數係π既陪數
所以:
2r=20
r=10
rθ=4π
10θ=4π
θ=0.4π rad. or θ=72度
b)陰影的面積
=扇形面積-三角形面積
=10(4π)-0.5*sin72 10^2
=78.1 cm^2 (取至3個有效數字)
c) 個三角形剩底個條邊既邊長^2
=10^2+10^2-2*10*10*cos 72
=200-200cos72
邊長=開方上面既答案
周界=邊長+4π
=24.3cm (取至3個有效數字)
2009-03-12 01:23:55 補充:
2)
a)[tan(90+θ)cos(θ+270)sin(90+θ)] /[cot(180-θ)sin(θ+270)]
=(cotθ sinθ cos θ)/[cotθ cos(-θ)]
(約去cotθ cosθ)
=-sinθ
2009-03-12 01:24:36 補充:
b)tan(π+θ)/[sin(π+θ) cos(3π-θ)] +[sin(4π-θ)sin(π+θ)]/{sin[(3π/2)+θ] cos(-θ-6π)}
=tan(180+θ)/[sin(180+θ) cos(540-θ)]+[sin(720-θ)sin(180+θ)/[sin(270+θ)cos-(θ+1080)]
=tanθ/sin-θ cos-θ+ (sin-θ sin-θ)/(cos-θ cosθ)
=tanθ/sinθ cosθ+ sin^2 θ/-cos^2 θ
2009-03-12 01:24:44 補充:
=(sinθ/cosθ)/sinθcosθ-tan^2 θ
=1/cos^2 θ-tan^2 θ
=sec^2 θ-tan^2 θ
=(tan^2 θ+1)-tan^2 θ
=1