Need help factoring: 5x^5-33x^4-14x^3?

First factor out an x^3
5x^2 - 33x - 14

x^3(5x + 2)(x - 7)

x = -2/5 , 7

5x^5 - 33x^4 - 14x^3
= x^2(5x^2 - 33x - 14)
= x^2(5x^2 + 2x - 35x - 14)
= x^2[(5x^2 + 2x) - (35x + 14)]
= x^2[x(5x + 2) - 7(5x + 2)]
= x^2(5x + 2)(x - 7)

First you can see that x^3 is a common factor so you can factor that out of the entire expression
x^3(5x^2-33x-14)
Now we need to find the factors of 5 and 14
5 only has 1 and 5
14 has 1&14 along with 2&7
We need to match up these numbers so that when added together they make -33
5 x -7 + 2 x 1 = 33
therefore the factored form is
x^3 (5x+2)(x-7)

= x^3(5x^2 - 33x - 14) = x^3(x - 7)(5x + 2)

5x^5-33x^4-14x^3

x^3(5x^2-33x-14)

x^3 ( 5x+2)(x-7)

x^3(5x^2-33x -14)=
=x^3(x-7)(5x+2)