Need help factoring: 5x^5-33x^4-14x^3?
回答 (6)
2009-03-09 2:36 pm
✔ 最佳答案
First factor out an x^35x^2 - 33x - 14
x^3(5x + 2)(x - 7)
x = -2/5 , 7
2009-03-09 11:26 pm
5x^5 - 33x^4 - 14x^3
= x^2(5x^2 - 33x - 14)
= x^2(5x^2 + 2x - 35x - 14)
= x^2[(5x^2 + 2x) - (35x + 14)]
= x^2[x(5x + 2) - 7(5x + 2)]
= x^2(5x + 2)(x - 7)
= x^2(5x^2 - 33x - 14)
= x^2(5x^2 + 2x - 35x - 14)
= x^2[(5x^2 + 2x) - (35x + 14)]
= x^2[x(5x + 2) - 7(5x + 2)]
= x^2(5x + 2)(x - 7)
2009-03-09 9:36 pm
First you can see that x^3 is a common factor so you can factor that out of the entire expression
x^3(5x^2-33x-14)
Now we need to find the factors of 5 and 14
5 only has 1 and 5
14 has 1&14 along with 2&7
We need to match up these numbers so that when added together they make -33
5 x -7 + 2 x 1 = 33
therefore the factored form is
x^3 (5x+2)(x-7)
x^3(5x^2-33x-14)
Now we need to find the factors of 5 and 14
5 only has 1 and 5
14 has 1&14 along with 2&7
We need to match up these numbers so that when added together they make -33
5 x -7 + 2 x 1 = 33
therefore the factored form is
x^3 (5x+2)(x-7)
參考: Math Major
2009-03-09 9:53 pm
= x^3(5x^2 - 33x - 14) = x^3(x - 7)(5x + 2)
2009-03-09 9:42 pm
5x^5-33x^4-14x^3
x^3(5x^2-33x-14)
x^3 ( 5x+2)(x-7)
x^3(5x^2-33x-14)
x^3 ( 5x+2)(x-7)
2009-03-09 9:41 pm
x^3(5x^2-33x -14)=
=x^3(x-7)(5x+2)
=x^3(x-7)(5x+2)
收錄日期: 2021-05-01 12:06:54
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