Factorize the following expressions.
( x-3)^2 - 4x^2
Maths F.2!!!
2009-03-10 1:50 am
回答 (3)
2009-03-10 2:36 am
✔ 最佳答案
( x-3)^2 - 4x^2= x^2 - 6x + 9 - 4x^2
= -3x^2 - 6x + 9
= (x+3) (x-1)
2009-03-11 22:17:00 補充：
= -3x^2 - 6x + 9
= -3 (x^2 + 2x -3)
= -3 (x+3) (x-1)
參考: 自己計
2009-03-12 5:13 am
1.( x-3)^2 - 4x^2
=( x-3)^2-(2x)^2
=(x-3+2x)(x-3-2x)
2009-03-11 21:30:32 補充：
=(3x-3)(-x-3)
=-3(x+3) (x-1) or
(x-3)^2 - 4x^2中三學
= x^2 - 6x + 9 - 4x^2
= -3x^2 - 6x + 9
= -3(x+3) (x-1)
2009-03-11 21:30:33 補充：
=(3x-3)(-x-3)
=-3(x+3) (x-1) or
(x-3)^2 - 4x^2中三學
= x^2 - 6x + 9 - 4x^2
= -3x^2 - 6x + 9
= -3(x+3) (x-1)
=( x-3)^2-(2x)^2
=(x-3+2x)(x-3-2x)
2009-03-11 21:30:32 補充：
=(3x-3)(-x-3)
=-3(x+3) (x-1) or
(x-3)^2 - 4x^2中三學
= x^2 - 6x + 9 - 4x^2
= -3x^2 - 6x + 9
= -3(x+3) (x-1)
2009-03-11 21:30:33 補充：
=(3x-3)(-x-3)
=-3(x+3) (x-1) or
(x-3)^2 - 4x^2中三學
= x^2 - 6x + 9 - 4x^2
= -3x^2 - 6x + 9
= -3(x+3) (x-1)
參考: me, me, me
2009-03-10 2:32 am
(x-3)^2-4x^2
=(x-3)^2-(2x)^2
=[(x-3)+(2x)][(x-3)-(2x)]
=(x-3+2x)(x-3-2x)
=(3x-3)(-x-3)
hope can help you!
SEE YOU¬
=(x-3)^2-(2x)^2
=[(x-3)+(2x)][(x-3)-(2x)]
=(x-3+2x)(x-3-2x)
=(3x-3)(-x-3)
hope can help you!
SEE YOU¬
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