請連同數式列出
x2 + 10x + 24 = 0
x2 + 1x - 12 = 0
x2 - 3x - 4 = 0
全部都係求x的值
尼幾條數點計？
2009-03-07 9:42 pm
回答 (3)
2009-03-08 1:09 am
✔ 最佳答案
x2 + 10x + 24 = 0(x + 6)(x + 4) = 0
x = - 4 , - 6
x2 + 1x - 12 = 0
(x + 4)(x - 3) = 0
x = - 4 , 3
x2 - 3x - 4 = 0
(x - 4)(x + 1) = 0
x = 4 , - 1
這幾條數需要用 Cross Method，
但我不在此詳細解釋了。
如果對以上回答唔明白，
可以睇下我系另一條問題有關 Cross Method ge 解釋。
http://hk.knowledge.yahoo.com/question/question?qid=7008100802140
參考: myself
2009-03-07 10:14 pm
1) x2 + 10x + 24 = 0
(x+4)(x+6)=0
x=-4 or x=-6
2) x2 + 1x - 12 = 0
(x+4)(x-3)=0
x=-4 or x=3
3)x2 - 3x - 4 = 0
(x-4)(x+1)=0
x=-1 or x=4
(x+4)(x+6)=0
x=-4 or x=-6
2) x2 + 1x - 12 = 0
(x+4)(x-3)=0
x=-4 or x=3
3)x2 - 3x - 4 = 0
(x-4)(x+1)=0
x=-1 or x=4
收錄日期: 2021-04-13 16:29:38
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20090307000051KK00847