-3p + 1 ≥ 16 (I think the book is wrong.)?

-3p + 1 ≥ 16
-3p ≥ 15
for the sake of explanation, i'll divide by 3 and not -3 this time
-p ≥ 5

okay, think of it like this. the opposite (negative) of your number is greater than 5. so the number itself must be less than -5, so that when you multiply that number by -1 you get something > 5. therefore, you have to "flip the sign" when you divide by negative 1. in reality, you have to flip the sign every time you divide or multiply by a negative

so divide by your -1. and flip the sign around the other way!

p ≤ -5

not in the book, you're right

-5 x -3 = 15 + 1 = 16
-3(-5) + 1 = 16
The answer is A. Anything less than -5 will make the equation less than 16. The symbol in your equation is greater than or equal to.

Same here. The book is wrong.

-3p + 1 ≥ 16
-3p ≥ 16 - 1
-3p ≥ 15
p ≤ 15/-3
p ≤ -5

damn your right the book is wrong and you are definitely right. nice i dont think anyone would have caught that mistake. call the company that makes the book and tell them they are wrong and you want your money back

D because when you devide by a negative the sighn switches

You're right. The book is in error.

D is probably supposed to show -5, but errors happen in math books too.

p ≤ -5 is the correct answer.