can you help me solve it?
and show the steps?
help me solve log(x+2)-log(x-2)=log5?
2009-03-05 10:50 am
回答 (4)
2009-03-05 11:31 am
✔ 最佳答案
log(x + 2) - log(x - 2) = log(5)log[(x + 2)/(x - 2)] = log(5)
(x + 2)/(x - 2) = 5
x + 2 = 5(x - 2)
x + 2 = 5x - 10
x - 5x = -2 - 10
-4x = -12
x = -12/-4
x = 3
2009-03-05 7:13 pm
log(x+2)-log(x-2)=log5
.......(x+2)
log----------=log5
........x-2
10^log(x+2)/(x-2) =10^log5
...x+2
------------- 5
...x-2
x+2=5(x-2)
x+2=5x-10
x-5x=-10-2
-4x=-12
x=3 answer//
.......(x+2)
log----------=log5
........x-2
10^log(x+2)/(x-2) =10^log5
...x+2
------------- 5
...x-2
x+2=5(x-2)
x+2=5x-10
x-5x=-10-2
-4x=-12
x=3 answer//
2009-03-05 7:05 pm
log [ (x + 2) / (x - 2) ] = log 5
(x + 2) / (x - 2) = 5
x + 2 = 5x - 10
12 = 4x
x = 3
(x + 2) / (x - 2) = 5
x + 2 = 5x - 10
12 = 4x
x = 3
2009-03-05 6:54 pm
log(x+2)-log(x-2)=log5
log((x+2)/(x-2)) = log5
(x+2)/(x-2) = 5
x+2=5x-10
12 = 4x
x = 3
log((x+2)/(x-2)) = log5
(x+2)/(x-2) = 5
x+2=5x-10
12 = 4x
x = 3
收錄日期: 2021-05-01 12:06:08
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