can someone please help me with this math equation?
回答 (5)
2009-03-05 10:28 am
✔ 最佳答案
x^0 = 13(1) + 3(1)
6
2009-03-05 10:50 am
3x^0 + (3x)^0
= 3(1) + 1
= 3 + 1
= 4
= 3(1) + 1
= 3 + 1
= 4
2009-03-05 10:41 am
3x^0 + (3x)^0
=3(1)+1
=3+1
=4 answer//
=3(1)+1
=3+1
=4 answer//
2009-03-05 10:27 am
Anything to the power 0 is 1, so:
x^0 = 1 so 3 x^0 = 3
(3x)^0 = 1
3 + 1 = 4
So the answer is 4, but this is not an equation.
x^0 = 1 so 3 x^0 = 3
(3x)^0 = 1
3 + 1 = 4
So the answer is 4, but this is not an equation.
2009-03-05 10:25 am
3x^0+(3x)^0=
3+1=4
3+1=4
收錄日期: 2021-05-01 12:14:16
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20090305022149AA32yd3