12(c^2+2)-2(c^2+2)^2-18
計極都唔岩,書中答案:
-2(c+1)^2(c-1)^2
唔係好明,我錦計的:
12(c^2+2)-2(c^2+2)^2-18
=-2(c^2+2)+12(c^2+2)-18
=-2[(c^2+2)^2-6(c^2+2)+9]
=-2[(c^2+2)^2-2(3)(c^2+2)+3^2]
=-2(c^2+2-3)^2
=-2(c^2-1)^2
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要詳細step,plx~
中二 因式分解
2009-03-05 6:40 am
回答 (1)
2009-03-05 6:55 am
✔ 最佳答案
12(c2+2)-2(c2+2)2-18= -2[(c2+2)-6(c2+2)-9]
=-2[(c2+1)-3]2
=-2(c2-1)2
=-2[(c+1)(c-1)]2
=-2(c+1)2(c-1)2
=]
參考: me
收錄日期: 2021-04-13 16:28:57
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20090304000051KK01938