could someone please show me the steps to solving 3(z-1)=5(2z-3)?

3(z-1)=5(2z-3)
or, 3*z - 3*1 = 5*2z - 5*3
or, 3z-3=10z-15
0r, --7z= --12
or, 7z=12
or, z=12/7

3 z - 3 = 5 z - 15
12 = 2 z
z = 6

3(x-4)=3 [divide by making use of three throughtout] (x-4)=0 [boost the bracket and convey the 4 over] x=4 it is erroneous by using fact 3/3 isn't equals to 0 yet to a million. so 3 (x-4) = 3 x - 4 = a million x = 4 + a million x = 5 you additionally can confirm it: 3 (5 - 4) = 3 3 = 3 a million = a million So it is the suitable root of the equation.

First thing to do is multiply what's in the parenthesis by what's outside:

3(z-1) = 5(2z-3) = 3z-3 = 10z - 15

The next step is to get your zs on one side of the equation ( don't forget to change the sign ) and your numbers on the other:

10z-3z = 15-3

And do the math:

7z = 12

YOu can leave it like that or express it in terms of z:

z = 12/7

Luck

3(z - 1) = 5(2z - 3)
3*z - 3*1 = 5*2z - 5*3
3z - 3 = 10z - 15
3z - 10z = 3 - 15
-7z = -12
z = -12/-7
z = 12/7

First expand the brackets
3xz - 3x1 = 5x2z - 5x3
3z-3=10z-15
Gather the unknowns to one side and the constants to the other
Subtract 3z from both sides
3z-3z-3 = 10z-3z-15
-3=7z-15
Add 15 to both sides
-3+15=7z-15+15
12=7z
Divide both sides by 7 to give the answer
z=12/7

You can then check this by substituting this into the formula
3(12/7 - 1) = 3x5/7 = 15/7
5(2x12/7-3) = 5(24/7-3) = 5x3/7 = 15/7

3z-3=10z-15
15-3=10z-3z
12=7z
z=12/7

3z-3 = 10z-15
-3+15 = 10z-3z
12 = 7z
so

z = 1.714

Its your homework, YOU sort it out.