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subtract 3y-y^2 from the sum of y^2-2 and 8y-8?
2009-03-01 3:37 pm
回答 (2)
2009-03-01 3:53 pm
✔ 最佳答案
[y^2-2]+[8y-8]-[3y-y^2]=y^2+8y-10-3y+y^2
=2y^2+5y-10 answer//
2009-03-01 11:42 pm
[(y^2 - 2) + (8y - 8)] - (3y - y^2)
= [y^2 - 2 + 8y - 8] - 3y + y^2
= y^2 + 8y - 10 - 3y + y^2
= 2y^2 + 5y - 10
= [y^2 - 2 + 8y - 8] - 3y + y^2
= y^2 + 8y - 10 - 3y + y^2
= 2y^2 + 5y - 10
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https://hk.answers.yahoo.com/question/index?qid=20090301073731AAP43F9