chem QQQQQuestion

2009-03-01 7:05 am

Q1


Which of the followings is the correct method to separate copper in the mixture of copper and its oxide?


(1) Heat the mixture and then collect the gas.


(2) Addition of dilute HCl into the mixture followed by filtration.


(3) Addition of concentrated H2SO4 into the mixture followed by distillation.


Q2


Copper(II) sulphate solution is blue in colour. When concentrated hydrochloric acid is added to this solution, a green solution is obtained.


Which of the following statements below are correct?


(1) Copper(II) ions are blue in colour


(2) Sulphate ions are colourless


(3) When concentrated HCl is added , blue copper(II) ions mixes with yellow chloride ions forming a green colour.





plz explain ...thanks for yr help...

回答 (2)

2009-03-01 8:50 am
✔ 最佳答案
Q1

(1) is incorrect.
When the mixture is heated, the copper reacts with oxygen in the air to give a black solid of copper(II) oxide.
2Cu + O2 → 2CuO
Therefore, copper(II) is left, but no gas is formed.

(2) is correct.
The oxide of copper dissolves in the acid, but copper does not react. After filtration, the residue obtained is copper.

(3) is incorrect.
Both copper and copper(II) oxide reacts with concentrated sulphuric acid to form a solution of copper(II) sulphate. The gas evolved is sulphur dioxide.
CuO + H2SO4 → CuSO4 + H2O
Cu + 2H2SO4 → CuSO4 + 2H2O + SO2

Q2

(1) is correct.
The aqueous solution of copper(II) ions is blue.

(2) is correct.

(3) is incorrect.
Chlorine ions are colourless, but not yellow. When concentrated hydrochloric acid is added to a solution of copper(II) sulphate, a green solution is formed. This is due to the formation of green [CuCl42-] complex.
Cu2+(aq) + 4Cl-(aq) → [CuCl42-](aq)
=
2009-03-01 7:23 am
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