Perform the indicated operations: √[50] + 2√[32] – √[8]?

2009-02-27 3:47 pm

回答 (7)

2009-02-27 3:52 pm
✔ 最佳答案
sqr (50) = sqr (25) * sqr (2) = 5 * sqr (2)

sqr (32) = sqr (16) * sqr (2) = 4 * sqr (2)

sqr (8) = sqr (4) * sqr (2) = 2 * sqr (2)

total = (5 + 2*4 -2) * sqr (2) = 11 * sqr (2)
2009-02-27 4:06 pm
√50 + 2√32 - √8
= √(5^2 x 2) + 2√(4^2 x 2) - √(2^2 x 2)
= 5√2 + 2(4)√2 - 2√2
= 5√2 + 8√2 - 2√2
= 13√2 - 2√2
= 11√2
2009-02-27 4:01 pm
√[50] + 2√[32] – √[8]
=√(25*2)+2√(16*2)-√(4*2)
=5√2+8√2-2√2
=11√2 answer//
2009-02-27 4:00 pm
sqrt(50)=5 sqrt(2)

sqrt(32)=4sqrt(2)

sqrt(8)=2sqrt(2)

We have:

5sqrt(2)+2(4sqrt(2))-2sqrt(2) which is 11 sqrt(2).

You can add the sqrt(2) coefficients together. It's just like adding all the x's together in an equation.
2009-02-27 3:57 pm
You need a calculator for this, but it's fairly easy.

Find the square root of 50 = (7.07)
Add 2 times the square root of 32 = 2x(5.66) = 11.32
7.07 + 11.32 = 18.39
Subtract the square root of 8 = 2.83

18.39 - 2.83 = 15.56
2009-02-27 3:53 pm
sqrt(5) = sqrt(25*2) = sqrt(5^2 * 2) = 5sqrt(2)
2sqrt(32) = 2sqrt(16*2) = 2sqrt(4^2 * 2) = 8sqrt(2)
-sqrt(8) = -sqrt(4*2) = -sqrt(2^2 * 2) = -2sqrt(2)

Add them all up and you get 11sqrt(2).

Hope that helps!
2009-02-27 3:53 pm
√50 + 2√32 – √8 =
√(25 * 2) + 2√(16 * 2) – √(4 * 2) =
5√2 + 2(4√2) - 2√2 =
3√2 + 8√2 =
11√2

ANSWER: 11√2


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