how do you solve n over 3 + 10=75?
I am getting 195 but the answer is -195. also please verify the following 3(2x+1)+x=(-39) and 4n+1-n=19 thanks
回答 (11)
✔ 最佳答案
n/3 + 10 = 75
n/3 = 75 - 10
n/3 = 65
n = 65(3)
n = 195
3(2x + 1) + x = -39
6x + 3 + x = -39
7x = -39 - 3
7x = -42
x = -42/7
x = -6
4n + 1 - n = 19
3n = 18
n = 18/3
n = 6
n / 3 + 10 = 75
n / 3 = 65
n = 195
6x + 3 + x = - 39
7x = - 42
x = - 6
3n = 18
n = 6
question is vague. several possibilities:
(n/3) + 10 = 75
n = 65*3 = 195
n/(3+10) = 75
n = 75*13 = 975
.
n/3 + 10 = 75
n/3 = 75 - 10
n = 3(65)
n = 195
3(2x + 1) + x = -39
6x + 3 + x = -39
6x + x = -39 - 3
7x = -42
x = -42/7
x = -6
4n + 1 - n = 19
4n - n = 19 - 1
3n = 18
n = 18/3
n = 6
1)
n/3 + 10 = 75
n/3 = 75 - 10
n = 3(65)
n = 195
2)
3(2x + 1) + x = -39
6x + 3 + x = -39
6x + x = -39 - 3
7x = -42
x = -42/7
x = -6
3)
4n + 1 - n = 19
4n - n = 19 - 1
3n = 18
n = 18/3
n = 6
1)
n/3 + 10 = 75
n/3 = 75 - 10
n = 3(65)
n = 195
2)
3(2x + 1) + x = -39
6x + 3 + x = -39
6x + x = -39 - 3
7x = -42
x = -42/7
x = -6
3)
4n + 1 - n = 19
4n - n = 19 - 1
3n = 18
n = 18/3
n = 6
If its (n/3)+10=75, then
n/3=75-10,
n/3=65,
n=3*65= 195.
n = 195,
x = -6 and
n = 6
The first answer can never be -195, where is that coming from?
(n/3) + 10 = 75
n/3 = 65
n = 195.
Are you reading the question properly? If it exactly as I read it, then maybe the answers are wrong. It happens sometimes.
3(2x+1) + x = -39
6x + 3 + x = -39
7x + 3 = -39
7x = -42
x = -6
4n + 1 - n = 19
3n + 1 = 19
3n = 18
n = 6
參考: My brain :-D
1)
n/3 + 10 = 75
n/3 = 75 - 10
n = 3(65)
n = 195
2)
3(2x + 1) + x = -39
6x + 3 + x = -39
6x + x = -39 - 3
7x = -42
x = -42/7
x = -6
3)
4n + 1 - n = 19
4n - n = 19 - 1
3n = 18
n = 18/3
n = 6
收錄日期: 2021-05-01 12:07:33
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20090227033354AAf1xP4
檢視 Wayback Machine 備份