how do you solve n over 3 + 10=75?

2009-02-27 11:33 am
I am getting 195 but the answer is -195. also please verify the following 3(2x+1)+x=(-39) and 4n+1-n=19 thanks

回答 (11)

2009-02-27 12:17 pm
✔ 最佳答案
n/3 + 10 = 75
n/3 = 75 - 10
n/3 = 65
n = 65(3)
n = 195

3(2x + 1) + x = -39
6x + 3 + x = -39
7x = -39 - 3
7x = -42
x = -42/7
x = -6

4n + 1 - n = 19
3n = 18
n = 18/3
n = 6
2009-03-01 2:46 am
n / 3 + 10 = 75
n / 3 = 65
n = 195

6x + 3 + x = - 39
7x = - 42
x = - 6

3n = 18
n = 6
2009-02-27 9:13 pm
question is vague. several possibilities:

(n/3) + 10 = 75
n = 65*3 = 195

n/(3+10) = 75
n = 75*13 = 975

.
2009-02-27 9:11 pm
n/3 + 10 = 75
n/3 = 75 - 10
n = 3(65)
n = 195

3(2x + 1) + x = -39
6x + 3 + x = -39
6x + x = -39 - 3
7x = -42
x = -42/7
x = -6

4n + 1 - n = 19
4n - n = 19 - 1
3n = 18
n = 18/3
n = 6
2009-02-27 8:36 pm
1)
n/3 + 10 = 75
n/3 = 75 - 10
n = 3(65)
n = 195

2)
3(2x + 1) + x = -39
6x + 3 + x = -39
6x + x = -39 - 3
7x = -42
x = -42/7
x = -6

3)
4n + 1 - n = 19
4n - n = 19 - 1
3n = 18
n = 18/3
n = 6
2009-02-27 8:31 pm
1)
n/3 + 10 = 75
n/3 = 75 - 10
n = 3(65)
n = 195

2)
3(2x + 1) + x = -39
6x + 3 + x = -39
6x + x = -39 - 3
7x = -42
x = -42/7
x = -6

3)
4n + 1 - n = 19
4n - n = 19 - 1
3n = 18
n = 18/3
n = 6
2009-02-27 8:11 pm
If its (n/3)+10=75, then
n/3=75-10,
n/3=65,
n=3*65= 195.
2009-02-27 7:51 pm
n = 195,
x = -6 and
n = 6

The first answer can never be -195, where is that coming from?
2009-02-27 7:41 pm
(n/3) + 10 = 75
n/3 = 65
n = 195.

Are you reading the question properly? If it exactly as I read it, then maybe the answers are wrong. It happens sometimes.

3(2x+1) + x = -39
6x + 3 + x = -39
7x + 3 = -39
7x = -42
x = -6

4n + 1 - n = 19
3n + 1 = 19
3n = 18
n = 6
參考: My brain :-D
2009-02-27 7:39 pm
1)
n/3 + 10 = 75
n/3 = 75 - 10
n = 3(65)
n = 195

2)
3(2x + 1) + x = -39
6x + 3 + x = -39
6x + x = -39 - 3
7x = -42
x = -42/7
x = -6

3)
4n + 1 - n = 19
4n - n = 19 - 1
3n = 18
n = 18/3
n = 6


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