solve by using the quadratic formula 4p^2=-25p-25?

4p^2+25p+25=0
x=(-25±√625-400)/8
x=(-25±15)/8
x=-10/8=-5/4
x=-40/8=-5

4p ^ 2 = -25 p - 25

4 p ^2 + 25 p + 25 = 0

4 p^2 + 20 p + 5 p + 25 = 0

4p ( p + 5) + 5( p + 5 ) = 0

(p + 5) (4p + 5 ) = 0

if p + 5 = 0

p = -5

or if 4p + 5 = 0

then p = -5/ 4

question variety a million : For this equation x^2 - 7*x - a million = - 7 , answer right here questions : A. discover the roots making use of Quadratic formula ! B. Use factorization to discover the muse of the equation ! C. Use finishing up the sq. to discover the muse of the equation ! answer variety a million : First, we would desire to teach equation : x^2 - 7*x - a million = - 7 , right into a*x^2+b*x+c=0 variety. x^2 - 7*x - a million = - 7 , pass each thing interior the suitable hand component, to the left hand component of the equation <=> x^2 - 7*x - a million - ( - 7 ) = 0 , it is the comparable with <=> x^2 - 7*x - a million + ( 7 ) =0 , now open the bracket and we get <=> x^2 - 7*x + 6 = 0 The equation x^2 - 7*x + 6 = 0 is already in a*x^2+b*x+c=0 variety. In that variety, we are able to easily derive that the fee of a = a million, b = -7, c = 6. 1A. discover the roots making use of Quadratic formula ! Use the formula, x1 = (-b+sqrt(b^2-4*a*c))/(2*a) and x2 = (-b-sqrt(b^2-4*a*c))/(2*a) We had know that a = a million, b = -7 and c = 6, we would desire to subtitute a,b,c interior the abc formula, with thos values. Which produce x1 = (-(-7) + sqrt( (-7)^2 - 4 * (a million)*(6)))/(2*a million) and x2 = (-(-7) - sqrt( (-7)^2 - 4 * (a million)*(6)))/(2*a million) it is the comparable with x1 = ( 7 + sqrt( 40 9-24))/(2) and x2 = ( 7 - sqrt( 40 9-24))/(2) Which make x1 = ( 7 + sqrt( 25))/(2) and x2 = ( 7 - sqrt( 25))/(2) So we get x1 = ( 7 + 5 )/(2) and x2 = ( 7 - 5 )/(2) So we've the solutions x1 = 6 and x2 = a million 1B. Use factorization to discover the muse of the equation ! x^2 - 7*x + 6 = 0 ( x - 6 ) * ( x - a million ) = 0 The solutions are x1 = 6 and x2 = a million 1C. Use finishing up the sq. to discover the muse of the equation ! x^2 - 7*x + 6 = 0 ,divide the two component with a million Then we get x^2 - 7*x + 6 = 0 , all of us know that the coefficient of x is -7 we would desire to apply the incontrovertible fact that ( x + q )^2 = x^2 + 2*q*x + q^2 , and anticipate that q = -7/2 = -3.5 So we've make the equation into x^2 - 7*x + 12.25 - 6.25 = 0 which could be grew to become into ( x - 3.5 )^2 - 6.25 = 0 So we are able to get (( x - 3.5 ) - 2.5 ) * (( x - 3.5 ) + 2.5 ) = 0 by making use of making use of the associative regulation we get ( x - 3.5 - 2.5 ) * ( x - 3.5 + 2.5 ) = 0 And it is the comparable with ( x - 6 ) * ( x - a million ) = 0 So we've been given the solutions as x1 = 6 and x2 = a million

4 p ² + 25 p + 25 = 0
x = [ - 25 ± √ (625 - 400 ) ] / 8
x = [ - 25 ± √ (225) ] / 8
x = [ - 25 ± 15 ] / 8
x = - 5/4 , x = - 5

Add 25p and add 25 to both sides to get this in ap^2+px+c=0 form:
4p^2+25p+25

The quadratic formula is:
p=[-b +/- sqrt(b^2-4ac)]/2a

Here, a=4, b=25, c=-25

Now, p=[-25 +/- sqrt(25^2-(4*4*25))]/(2*4)
p=[-25 +/- 15]/8
p=-5 or p=-10/8=-1.25

Check out my eHow article that deals with how to use the quadratic formula to solve quadratic equations.
http://www.ehow.com/how_4816180_quadratic-equation-using-quadratic-formula.html

4p^2=-25p-25

4p^2+25p+25=0

4p+5 p+5=0

p=-5/4 or -5

4p^2 = -25p - 25
4p^2 + 25p + 25 = 0
p = [-b ±√(b^2 - 4ac)]/2a

a = 4
b = 25
c = 25

p = [-25 ±√(625 - 400)]/8
p = [-25 ±√225]/8
p = [-25 ±15]/8

p = [-25 + 15]/8
p = -10/8
p = -5/4 (-1.25)

p = [-25 - 15]/8
p = -40/8
p = -5

∴ p = -5 , -5/4 (-1.25)

1. Equate the whole equation to 0 (a+b+c=0)
thus, 4p^2 + 25p +25 = 0
where a=4, b=25, c= 25

2. Substitute the corresponding values to the quadratic formula (which is [-b ± √(b^2 - 4ac)]/2a)
thus, [-25 ± √(25^2 - 4*4*25)] / (2*4)

3. You will get: (-25 ± 15)/8 or:
a) (-25 + 15)/8 = -1.25
b) (-25 - 15)/8 = -5

4p^2 + 25p + 25=0

so first find the discriminant of the given equaition
so you get
D = b^2 - 4*a*c

= 25^2 - 4* 4 * 25

= 625 - 400

= 225

so p = - b +/- square root(D)
--------------------------------
2a

p = -25 +/- 15
---------------
8

p = (-25 + 15 ) / 8 and p= ( -25 - 15 ) / 8

so you get

p = - 5 / 4 , -5

First set the equation to the form ap² + bp + c
4p² = -25p - 25
4p² + 25p + 25 = 0

Use the quadratic formula to solve
   ap²+bp+c=0
where
   a=4
   b=25
   c=25

p = [-b ± √(b²-4ac)] / (2a)
   = [-(25) ± √((25)² - 4(4)(25))] / (2·4)
   = [-25 ± √225] / 8
   = [-25 ± 15] / 8

p₁ = (-25 - 15)/8
= -40/5
= -5

p₂ = (-25 + 15)/8
= -10/8
= -1.25