ALGEBRA HELP...how do you explain this problem?

Of course.
28 is divisible by 7 4 times meaning that seven lots iof something to equal 28 has to be four. The use of the negative numbers is only there to confuse you

- 7 m = - 28
7 m = 28
m = 4

-7M = -28
M = -28/-7
M = 4

yeah you are absolutely right !!!
-7m = -28
m = -28/-7 {we divide -7 as the side changes so the sign also changes!}
m = 4

There you go!

so you're solving for M, right?
in order to do that, you must remove the numerical coefficient "7", by dividing it by itself to regain an answer of "1".
and when you divide M by 7, you will also divide 28 by 7, because the rule is, what you do to one side, you must do to other.
and then multiply both sides by negative one, to have "M" as positive.
Steps:
-7M=-28
-7M/7=-28/7
-M=-4
-1(-M=-4)
M=4

U R right

-7m=-28
7m=28
m=28/7 (7 times 4 equals 28, and 28>7 so m>1)
m=4

yeah you are right
to get rid of 7 to get m, you should divide both sides by -7
-7m = -28
-7m = -28
-7m/-7 = -28/-7
-m = -4
m=4

Yeah... m=4...

-7m=-28

you need to divide both sides by -7...

-7m/-7 = m... and
-28/-7 = 4... therefore, m=4... you can check it by substituting m by 4 in the equation... -7(4) = -28

-7m = -28
7m = 28
m = 28 / 7
m = 4

yes u r right

as -7M= -28
M= -28/-7
M=4