請解答以下問題：
欣欣現有$510。她周一至周—五每天有$28，周六和周日沒有零用錢。樂樂現時沒有零用錢，她周一至周—五每天有$36, 周六和周日沒有零用錢。請問樂樂要花多少天，零用錢才能比欣欣多？
Try to solve the question below：
Yannes has now $510. On Monday to Friday, she has $28 a day but no pocket money on Saturday and Sunday. Lottie has no pocket money currently. She has $36 from Monday to Friday and has no money on Saturday and Sunday. How many days does Lottie need to have more pocket money than Yannes?
＊ 欣欣現時已有 $510。
Yannes has $510 currentenly.
＊ 樂樂的零用錢增加時欣欣的零用錢同時亦增加。
Yannes and Lottie's pocket money increases at the same time.
＊ 欣欣和樂樂周六和周日皆沒有零用錢
Yannes and Lottie both do not have pocket money on Sat and Sun.
數學難題一條 (Chinese & English 版)
2009-02-27 3:50 am
回答 (3)
2009-02-28 5:48 am
欣欣現有$510。她周一至周—五每天有$28，周六和周日沒有零用錢。樂樂現時沒有零用錢，她周一至周—五每天有$36, 周六和周日沒有零用錢。請問樂樂要花多少天，零用錢才能比欣欣多？
設X為所需的天數。
欣欣本來$510
510+28X=36X
8X=510
X=63.5
所以樂樂要花64天，零用錢才能比欣欣多(36*64-(510+28*64)=2元)
驗算：
510+28*63.75-36*63.75=0
所以樂樂要63.75天，金錢才可以跟欣欣的相等
所以剛好64天後，樂樂的錢才可以超越欣欣
設X為所需的天數。
欣欣本來$510
510+28X=36X
8X=510
X=63.5
所以樂樂要花64天，零用錢才能比欣欣多(36*64-(510+28*64)=2元)
驗算：
510+28*63.75-36*63.75=0
所以樂樂要63.75天，金錢才可以跟欣欣的相等
所以剛好64天後，樂樂的錢才可以超越欣欣
2009-02-28 3:52 am
The Number of days she need to have more pocket money than Yannes
=510/(36-28)+(510/(36-28))/7*2
=63.75+18.12
=71.87
so,she need 72 days to have more pocket money than Yannes
=510/(36-28)+(510/(36-28))/7*2
=63.75+18.12
=71.87
so,she need 72 days to have more pocket money than Yannes
參考: Me
2009-02-27 4:00 am
要64日才能比欣欣多,因$36-$28=$8,那麼(8)(64)=512元
收錄日期: 2021-04-15 20:02:42
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20090226000051KK01501