✔ 最佳答案
The minimum value x0 of Gamma(x) for real positive x=x0 is achieved when
Gamma^'(x0)=Gamma(x0)psi_0(x0)=0
psi_0(x_0)=0.
This can be solved numerically to give x0=1.46163... (Sloane's A030169; Wrench 1968), which has continued fraction [1, 2, 6, 63, 135, 1, 1, 1, 1, 4, 1, 38, ...] (Sloane's A030170). At x0, Gamma(x0) achieves the value 0.8856031944... (Sloane's A030171), which has continued fraction [0, 1, 7, 1, 2, 1, 6, 1, 1, ...] (Sloane's A030172).