9x^2y^2-12xy+4=0.
find value of y
How solve this quadratic equation? 9x^2y^2-12xy+4=0?
2009-02-22 12:51 pm
回答 (5)
2009-02-22 12:59 pm
✔ 最佳答案
9x^2y^2-12xy+4=0(3xy-2)(3xy-2)=0
3xy-2=0 3xy-2=0
3xy=2 3xy=2
y=2/3x y=2/3x
y= 2/3x, 2/3x answer//
2009-02-22 12:56 pm
let 3xy=k
k^2-4k+4=0
(k-2)^2=0
k=2
3xy=2
xy=2/3
y=2/3x
k^2-4k+4=0
(k-2)^2=0
k=2
3xy=2
xy=2/3
y=2/3x
2009-02-22 2:25 pm
9x^2y^2 - 12xy + 4 = 0
9x^2y^2 - 6xy - 6xy + 4 = 0
(9x^2y^2 - 6xy) - (6xy - 4) = 0
3xy(3xy - 2) - 2(3xy - 2) = 0
(3xy - 2)(3xy - 2) = 0
3xy - 2 = 0
3xy = 2
y = 2/(3x)
â´ y = 2/(3x)
9x^2y^2 - 6xy - 6xy + 4 = 0
(9x^2y^2 - 6xy) - (6xy - 4) = 0
3xy(3xy - 2) - 2(3xy - 2) = 0
(3xy - 2)(3xy - 2) = 0
3xy - 2 = 0
3xy = 2
y = 2/(3x)
â´ y = 2/(3x)
2009-02-22 1:32 pm
9x^2y^2 -12xy +4= 0.
Quadratic formula = x=-b±â(b²-4ac)
____________
2a
a= 9
b= -12
c= 4
Quadratic formula = x=-b±â(b²-4ac)
____________
2a
a= 9
b= -12
c= 4
2009-02-22 1:11 pm
(3xy)^2 - 4(3xy -1) = 0 maybe . . .?
Can you see where this would help . . .I can't . . .?
Can you see where this would help . . .I can't . . .?
參考: ahhh . . .yeah . . .it's got the 'look' . . .just didn't register
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