f(x)=√(1-x^2) 求 f'(1/2)
dy/dx=x-2y/2x-2y 求 y''
2 條dy/dx 急!!
2009-02-23 3:57 am
回答 (2)
2009-02-23 5:29 am
2009-02-23 8:58 pm
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